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Search: id:A076624
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| A076624 |
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Sum of the non-divisors of n between 1 and n is a perfect square. |
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+0 1
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| 1, 2, 5, 6, 14, 149, 158, 384, 846, 5065, 8648, 181166, 196366, 947545, 5821349, 55867168, 491372910
(list; graph; listen)
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OFFSET
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1,2
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COMMENT
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Define b(0)=2, b(1)=5 and b(n)=6*b(n-1)-b(n-2)-2 for n>1. A prime number p is in the sequence iff (p^2-p-2)/2 is a square iff p=b(n) for some n. The next prime in the sequence is b(21)=8946229758127349, followed by b(n) for n=33, 51, 57 and 75.
a(18) > 3*10^9. [From Donovan Johnson (donovan.johnson(AT)yahoo.com), Oct 14 2009]
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FORMULA
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s(n)=A000217[n]-A000203[n]=A024816[n] is a square.
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EXAMPLE
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The sum of the non-divisors of 14 between 1 and 14 is 3 + 4 + 5 + 6 + 8 + 9 + 10 + 11 + 12 + 13 = 81 = 9^2. 1, 2, 7 & 14 are divisors. Hence 14 is a term of the sequence.
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MATHEMATICA
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Select[ Range[14*10^6], IntegerQ[Sqrt[(# (# + 1)/2) - DivisorSigma[1, # ]]] &]
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CROSSREFS
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Sequence in context: A100630 A057302 A109784 this_sequence A050216 A037079 A101325
Adjacent sequences: A076621 A076622 A076623 this_sequence A076625 A076626 A076627
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KEYWORD
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nonn
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AUTHOR
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Joseph L. Pe (joseph_l_pe(AT)hotmail.com), Oct 22 2002
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EXTENSIONS
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Edited by Robert G. Wilson v (rgwv(AT)rgwv.com) and Dean Hickerson (dean.hickerson(AT)yahoo.com), Oct 25 2002
a(16)-a(17) from Donovan Johnson (donovan.johnson(AT)yahoo.com), Oct 14 2009
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