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Search: id:A127629
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| A127629 |
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Numbers n such that a divisor, together with its quotient and remainder, are consecutive terms (in that order) in a geometric sequence. |
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+0
1
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| 9, 28, 34, 58, 65, 75, 110, 126, 132, 201, 205, 217, 224, 246, 254, 258, 294, 344, 384, 399, 436, 498, 502, 513, 516, 520, 579, 657, 680, 690, 730, 786, 810, 866, 880, 978, 979, 1001, 1008, 1028, 1038, 1105, 1128, 1164, 1330, 1332, 1365, 1370, 1374, 1388
(list; graph; listen)
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OFFSET
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1,1
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COMMENT
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The sequence misses the primes.
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LINKS
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C. Hughes, Geometric Division
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EXAMPLE
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58 is in the sequence because 58 = 9*6 + 4, where 9, 6 and 4 are consecutive terms in a geometric sequence.
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PROGRAM
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(PARI) a(n)={for(d=1, n, if((n\d)*(n%d)==d^2, return(1))); return(0)}
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CROSSREFS
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Sequence in context: A031454 A044999 A155473 this_sequence A024670 A141805 A124360
Adjacent sequences: A127626 A127627 A127628 this_sequence A127630 A127631 A127632
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KEYWORD
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easy,nonn
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AUTHOR
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Nick Hobson (nickh(AT)qbyte.org), Jan 20 2007
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